Results of Eight Dice[]
There's more than two ways to read the dice. For all these methods, I'm assuming the only significant information for each die is the count of pips on the dieface opposite the surface the die landed on once it stops moving. (Won't say "facing up," because gravity could be fucked up where you're rolling them.)
- Sum all the numbers
- This has the advantage of adding up quickly, but Trollkind (and Vriska in particular) likely have better dice-counting abilities than mere humans. The results would be numbers from 8-64, on bell-curve centred on 36, with results closer to 36 appearing more likely.
#!/usr/bin/perl
$amalgam8d_sum = 0;
for ($a=1; $a<=8; $a++) { $amalgam8d_sum+=int(rand(8)+1); }
print "The f8d number will 8e: ",$amalgam8d_sum,"\n";
- Digits of a base-9 number, one at a time
- You would roll each die once, and multiply the result by 8^(how many dice already rolled). So rolling "7" and "5" would be (7*8^0 + 5*8^1) = 47. With eight dice, you would get a number between 5380840 and 43046720 (37,665,880 possible combinations). It could be a base-8 number, but you'd have to subtract 1 from the value showing on each die first, to get digits 0-7.
- This method also sucks because you need to keep track of the order you roll the dice in, you can't just roll them all at once (unless you're Trollkind with Vision Eightfold, I guess).
#!/usr/bin/perl
$num8ber = "";
for ($place=1; $place<=8; $place++) { $num8er = int(rand(8)+1).$num8er; }
print "This is the num8er you w8d for: ",$num8er,"\n";
- Matching sets
- This is the least sucking method. Roll all the dice, then sort them. You'll need to look up the results on a table, but that's what a Strife Specibus is for, to keep track of that.
#!/usr/bin/perl
@your_8unch_of_diiiiiiiice = ();
for ($x=1; $x<=8; $x++) { push(@your_bunch_of_diiiiiiiice,int(rand(8)+1)); }
print "The or8cles of f8 say: ";
print join(',',sort(@your_bunch_of_diiiiiiiice)),"\n";
- The results table would have 6,435 entries, and not all entries have the same probability. Results of all the same face showing ('11111111' through '88888888') would be the most rare, each appearing only once in the entire table. The most common would be '12345678', appearing 40320/16777216 times (0.2% of total!).
#!/usr/bin/perl
# oh my g8d t8ks toooooooo l8ng to run
# i have bett8r th8ngs to do f8rget this
$meaniiiiiiiingless_count=00000000;
%duplic8_num8ers = ();
while ($meaniiiiiiiingless_count <= 077777777) {
$diiiiiiiice = sprintf("%08o",$meaniiiiiiiingless_count);
$diiiiiiiice = join("",sort(split(//,$diiiiiiiice)));
$duplic8_num8ers{"$diiiiiiiice"}++;
$meaniiiiiiiingless_count++;
}
print "How many cr8s for diiiiiiiice: ",scalar(keys(%duplic8_num8ers)),"\n";
END {
if (localtime() > 1/0) {
system("
");
}
}
--Mozai 18:47, July 27, 2010 (UTC)
I have no idea what you're talking about[]
It says on this page
that there are a field of fully 8^8 possible results. Is there any ambiguity about that?
--recognizer 01:32, July 31, 2010 (UTC)
There sure is. So far we know:
- There are 8*8*8*8*8*8*8*8 (16,777,216) possible permutations of the dice.
- This fact is explicitly stated, but we know it a priori anyways, because it would be pointless to use all eight dice unless each were significant.
- We can deduce from this fact that some rolls are considered "higher" than others, and thus all the rolls can be sorted in a sequential order. We don't know if that sequence is continuous (i.e.: 1,2,3... n+6,n+7,n+8). We don't know if each roll corresponds uniquely to a single technique.
- One die's value can "narrow the field down from the full 8^8
"
- We can deduce that the last die can be the significant difference between eight techniques.
All three methods mentioned above satisfy the conditions of these known facts. The "sum everything" method can have 57 possible techniques and it is the easiest to roll. The second method can have up to 16 million techniques and it's annoying to roll because you have to wait for each die one-at-a-time to finish moving. The third method can have up to 6,435 possible techniques and requires less mental arithmetic than the first method. Maybe there's some fourth trollknown method that I'm too pink and wriggly to figure out. --Mozai 17:06, July 31, 2010 (UTC)
Uhm. 8^8 and 8*8*8*8*8*8*8*8 are the same exact thing. Majutsukai 04:44, August 1, 2010 (UTC)
"All three methods mentioned above satisfy the conditions of these known facts."
If there are only 57 techniques, or only 6,435 techniques, how is there a field of 8^8 possible results? If there are 8^8 possible results, there are not six thousand results, or 57 results - there are 16 million results. recognizer 19:13, August 2, 2010 (UTC)
I am going to take a pre-meditated stab at this and assert that different permutations of the same set of single die rolls cannot (or should not) be distinguished, since the dice are co-identical. Therefore there really are only 6435 distinguishable outcomes and Andrew's discrete-mathematical intuition merely slipped when mentioning 8^8. I'm submitting this idea for approval/discourse before changing the page to reflect it. --BugQ 22:46, August 21, 2010 (UTC)
Catenative DDC[]
I added that weapon to this page because technically it involves dice, and just like some of john's hammer weapons, while it is too large to carry, it can still be used to fight. Loverdesang 09:39, September 12, 2010 (UTC)
Renaming[]
I just thought I'd draw to your attention [[Talk:Strife Deck#Since i have nowhere better to put this...|my comments on the Strife Deck talk page]]. File:Signoff3.gif- Janaro out. 17:58, November 25, 2010 (UTC)
Roll for "Ridiculous hat"[]
According to this page, rolling an 8 as the final number results in the "RIDICULOUS HAT" attack. However, according to the next page, the final die came up as a 7. Is it worth point this out in the article? Player_03 t/c 18:59, April 22, 2013 (UTC)
- Thanks for pointing it out! I've been aware of it since those pages were published, but I guess we failed to actually include it in the article. Aepokk Venset 20:44, April 22, 2013 (UTC)
'Fluorite' Octet[]
We have seen Vriska using this, and John using the hammer, which was probably prototyped with the Fluorite Octet. There is a form of octet called 'Blue John' 86.84.56.169 15:31, June 18, 2015 (UTC)